Could someone please check my Chemistry homework?
The molecular formula for cisplatin, a chemotherapy agent, is PtCl2(NH3)2
(The numbers are all supposed to be subscripts)
1. What is the molar mass of cisplatin?
Ans: 300.06 g/mol
2. How many moles of hydrogen atoms are in one mole of cisplatin?
Ans: 6
3. How many molecules are in 10.0g of cisplatin?
Ans: 2.01 x 10^22
All of these are correct. I'm sorry I didn't notice the post earlier.
To check your Chemistry homework, we need to calculate the molar mass of cisplatin and then answer the given questions.
1. Molar mass of cisplatin:
To find the molar mass, we need to calculate the sum of the atomic masses of all the atoms present in the molecule. Using the periodic table, we can find the atomic masses of the elements:
Pt (platinum) = 195.08 g/mol
Cl (chlorine) = 35.45 g/mol
N (nitrogen) = 14.01 g/mol
H (hydrogen) = 1.01 g/mol
Now, let's calculate the molar mass of cisplatin:
2(195.08 g/mol) + 2(35.45 g/mol) + 2(2[1.01 g/mol] + 14.01 g/mol) = 300.06 g/mol.
Therefore, the molar mass of cisplatin is 300.06 g/mol.
2. Moles of hydrogen atoms in one mole of cisplatin:
From the molecular formula, we can see that there are two NH3 groups in one mole of cisplatin. Each NH3 group contains three hydrogen atoms (H). So, there are a total of 2(3) = 6 hydrogen atoms in one mole of cisplatin.
Hence, there are 6 moles of hydrogen atoms in one mole of cisplatin.
3. Number of molecules in 10.0g of cisplatin:
To find the number of molecules, we need to use the following steps:
a. Calculate the moles of cisplatin:
Using the molar mass of cisplatin, we can calculate the moles by dividing the given mass by the molar mass:
Moles = mass / molar mass = 10.0g / 300.06 g/mol = 0.0333 mol (approximately)
b. Apply Avogadro's number:
One mole of any substance contains 6.022 x 10^23 molecules. So, to find the number of molecules in 0.0333 mol of cisplatin, we can multiply the moles by Avogadro's number:
Number of molecules = 0.0333 mol x 6.022 x 10^23 molecules/mol = 2.01 x 10^22 molecules.
Therefore, there are approximately 2.01 x 10^22 molecules in 10.0g of cisplatin.
I hope this helps you check your Chemistry homework!