Hi,
I have to draw a dot and cross diagram for NH2+ and then state the bond angles. I have done NH2-, but I am not sure how to do the + one.
I would take the structure you've drawn for NH2^- and remove one pair of the two lone pairs. It leaves an ion that doesn't obey the rule of eight but I don't see another way to do it.
Ok, thank you. That was the only way I could think of doing it too. What would the bond angles therefore be?
To draw a dot and cross diagram for NH2+, we first need to determine the valence electrons of each atom in the molecule.
In NH2+, the nitrogen atom (N) has five valence electrons, and the two hydrogen atoms (H) each have one valence electron. The plus sign indicates that the nitrogen has lost one electron, resulting in a positively charged ion.
To represent the valence electrons in the dot and cross diagram, we can follow these steps:
1. Start with the nitrogen (N) atom in the center and symbolize it with the letter N.
2. Draw the valence electron configuration for nitrogen as three pairs of dots around the N. This indicates the original five valence electrons it possesses.
3. Place the hydrogen (H) atoms on either side of the nitrogen atom.
4. Each hydrogen (H) atom brings its single valence electron, represented by a single dot, to share with the nitrogen (N) atom. Place one dot adjacent to each H atom.
5. Since the nitrogen (N) ion has lost one electron, it will have an empty orbital. Show this by leaving one of the valence electron pairs on the nitrogen (N) atom empty.
After following these steps, you should have a dot and cross diagram for NH2+ where the nitrogen atom is in the center, with three pairs of dots around it representing its five valence electrons, and two hydrogen atoms (H) on either side, each sharing a single valence electron with the nitrogen atom.
Regarding the bond angles, NH2+ has a trigonal pyramidal shape due to its sp3 hybridization. The bond angle between the nitrogen and each hydrogen atom will be approximately 107 degrees.