A 5kg mass is dropped from a height of 30m above the ground. Determine the velocity of the mass when it is 18n above the ground take = 10m/s2
v = vi - g t
h = ho - 4.9 t^2
18 = 30 - 4.9 t^2
t^2 = 2.45
t = 1.56 seconds
v = 0 - 9.8* 1.56
v = - 15.3 m/s
or
15.3 m/s down
5kg Mass dropped, height 30m,velocity 18m determined velocity
To determine the velocity of the mass when it is 18m above the ground, we can use the laws of motion. Specifically, we can use the equation for motion under gravity.
We have the following information:
- Initial height (h1) = 30m
- Final height (h2) = 18m
- Acceleration due to gravity (g) = 10m/s^2
We can determine the time it takes for the mass to fall from the initial height to the final height by using the equation for displacement under constant acceleration:
h2 = h1 + (v1 * t) + (1/2 * g * t^2)
Substituting the given values, we have:
18 = 30 + (0 * t) + (1/2 * 10 * t^2)
18 = 30 + 5t^2
5t^2 = 12
t^2 = 12/5
t^2 = 2.4
t ≈ √2.4
t ≈ 1.549
Now that we have the time it takes for the mass to reach 18m above the ground, we can determine the velocity at that point using the equation:
v2 = v1 + (g * t)
Substituting the given values:
v2 = 0 + (10 * 1.549)
v2 ≈ 15.49 m/s
Therefore, the velocity of the mass when it is 18m above the ground is approximately 15.49 m/s.