S = n/2 (a+1)
The subject of the formula is L
Same as before, please include workings TYVM
There is no L in your formula.
You seem to be confusing 1, l and L.
You still need to know how to use parentheses to avoid ambiguity in typed equations.
Oh sorry yes that's what i mean:
S = (n/2)*(a+L)
S = (n/2)*(a+L)
S/(n/2) = a + L
2*S / n = a + L
(2*S / n) - a = L , or
L = (2*S / n) - a
To make the subject of the formula L, we need to rearrange the equation S = (n/2)(a + 1).
1. Start by multiplying both sides of the equation by 2 to eliminate the fraction:
2S = n(a + 1).
2. Next, divide both sides of the equation by n to isolate (a + 1):
(2S)/n = a + 1.
3. Now, subtract 1 from both sides to obtain the value of a:
(2S)/n - 1 = a.
4. Finally, simplify the equation to get the subject L:
L = (2S - n) / n.
Therefore, the subject of the formula S = (n/2)(a + 1) is L, and it can be expressed as L = (2S - n) / n.