Wha are the roots of x to the second power divided by x minus six equals Zero?

Can you type out the problem? Maybe then people can actually help you. By reading what you said it sounds like it's

sq (x^2/x-6) = 0... but I guess that's not what the problem looks like, be sure you indicate where the parentheses are in your problem.

there are no parentheses in the problem its excatly what you wrote.

To find the roots of the equation x^2 / (x - 6) = 0, we need to set the equation equal to zero and solve for x.

First, we need to recognize that the numerator, x^2, will only be equal to zero if x is equal to zero.

Next, we need to consider the denominator, x - 6. For the equation to be equal to zero, the denominator cannot be zero. So, x - 6 ≠ 0.

Now, we can set up the equation x - 6 ≠ 0. By adding 6 to both sides, we get x ≠ 6.

Therefore, the equation has one root which is x = 0. The root x = 6 is excluded.

So, the only root of the equation x^2 / (x - 6) = 0 is x = 0.