Help!!!!!!
A confidence interval estimate for the population mean is given to be (39,90, 48.11) If the standard deviation is 11.473 and the sample size is 52 determine the maximum error of the estimate. determine the confidence level used for the given confidence interval
What level of confidence are you talking about?
??% confidence interval = mean ± ?? SEm
SEm = SD/√n
To determine the maximum error of the estimate, we need to calculate the margin of error, which is half the width of the confidence interval.
The given confidence interval is (39.90, 48.11). To find the maximum error, we subtract the lower value from the upper value:
48.11 - 39.90 = 8.21
Therefore, the maximum error of the estimate is 8.21.
To determine the confidence level used for the given confidence interval, we need to understand that confidence intervals are constructed based on a chosen level of confidence. In this case, we are not given the exact confidence level used.
However, we can make an inference based on a common practice. The most commonly used confidence level is 95%. This means that if we took multiple samples and constructed confidence intervals using the same method, approximately 95% of the intervals would contain the true population mean.
So, even though not specified, we can assume the confidence level used for the given confidence interval is likely to be 95%.