what is the torque generated to hold a 60N dumbell at 90 degrees? The dumbell is 0.6m from the shoulder, the centre of the mass of arm weighs 30N and is .25m from the shoulder, the moment arm is 0.05m?
To calculate the torque generated to hold a dumbbell in this scenario, we need to consider the forces involved and their respective moment arms.
First, let's identify the forces at play:
1. The weight of the dumbbell, which is given as 60N.
2. The weight of the arm, which is given as 30N.
Next, let's determine the moment arms for each force:
1. The moment arm for the dumbbell is given as 0.6m.
2. The moment arm for the weight of the arm is given as 0.25m.
3. The moment arm for the torque is given as 0.05m.
Now we can calculate the torque generated by each force and then sum them up to find the total torque.
For the dumbbell:
Torque_dumbbell = weight_dumbbell x moment_arm_dumbbell
= 60N x 0.6m
= 36 Nm
For the weight of the arm:
Torque_arm = weight_arm x moment_arm_arm
= 30N x 0.25m
= 7.5 Nm
Finally, we can find the total torque by adding the torques from both the dumbbell and the arm weight.
Total torque = Torque_dumbbell + Torque_arm
= 36 Nm + 7.5 Nm
= 43.5 Nm
Therefore, the torque generated to hold the 60N dumbbell at 90 degrees is 43.5 Nm.