what is the molarity of NaF in the final solution if a solution was prepared by mixing 35.0mL of 0.200M NaF with 28.5mL of 0.350M NaF
divide total solute by total volume of solution
solute: .035*.200 + .0285*.350 = .016975
solution: .035 + .0285 = .0635
so, we have .016975 moles/.0635L = .267M
To find the molarity of NaF in the final solution, we need to first calculate the total number of moles of NaF in the solution.
We can use the formula:
moles = concentration (M) × volume (L)
For the 35.0 mL of 0.200 M NaF:
moles1 = 0.200 M × 0.035 L
For the 28.5 mL of 0.350 M NaF:
moles2 = 0.350 M × 0.0285 L
Next, we can calculate the total moles of NaF by adding these two quantities together:
total moles of NaF = moles1 + moles2
To get the molarity of NaF in the final solution, we divide the total moles of NaF by the total volume of the solution in liters:
Molarity (M) = total moles of NaF / total volume of solution (L)
Now we can plug in the values and calculate the molarity:
Molarity = (moles1 + moles2) / (0.035 + 0.0285) L
Remember to always convert the volume from milliliters (mL) to liters (L) before calculating the molarity.
Let's calculate it: