starting from rest, a ball rolss, down an incline ata constant acceleration of 2meters per second
what is the velocity of the ball after 8.5 seconds?
how far does the ball roll in 10 seconds?
any one can help pleasse im stuck
To find the velocity of the ball after 8.5 seconds, we can use the equation of motion:
v = u + at
Where:
v = final velocity
u = initial velocity (in this case, 0 m/s since the ball starts from rest)
a = acceleration (2 meters per second per second)
t = time (8.5 seconds)
Substituting the values into the equation, we get:
v = 0 + 2 * 8.5
v = 17 meters per second
So, the velocity of the ball after 8.5 seconds is 17 meters per second.
To find how far the ball rolls in 10 seconds, we can use the equation of motion:
s = ut + 0.5at²
Where:
s = distance
u = initial velocity (0 m/s)
t = time (10 seconds)
a = acceleration (2 meters per second per second)
Substituting the values, we have:
s = 0 * 10 + 0.5 * 2 * (10)²
s = 0 + 0.5 * 2 * 100
s = 0 + 1 * 100
s = 100 meters
Therefore, the ball rolls a distance of 100 meters in 10 seconds.
I hope that helps!