Solve for X to three significant digits.
9^(2x)=11^(3x-2)
take logs to get rid of the exponents
2x ln9 = (3x-2)ln11
x(2 ln9 - 3 ln11) = -2 ln11
x = -2 ln11/(2 ln9 - 3 ln11)
x = -4.79/-2.8
x = 1.71
9^(2x)=11^(3x-2)
2x ln9 = (3x-2)ln11
x(2 ln9 - 3 ln11) = -2 ln11
x = -2 ln11/(2 ln9 - 3 ln11)
x = -4.79/-2.8
x = 1.71