this is the last problem on my homework and I JUST CANT GET THE RIGHT ANSWER!! Help. :/
limit as x -> -infinity of:
(1-(3/x))^2x
You know that lim(1 + 1/x)^x = e
let u = x/3, so x = 3u
lim(1 + 3/x)^2x = lim(1 + 1/u)^(6u)
= lim((1 + 1/u)^u)^6 = e^6
If you do a web search for "limit 1+a/x^bx" the first site shows a way to evaluate it using L'Hospital's Rule.