How many grams of NaOH (MW = 40.0) are there in 100.0 mL of a 0.275 M NaOH solution?
moles = M x L = ?
grams = moles x molar mass
How many grams of NaOH (MW = 40.0) are there in 300.0 mL of a 0.100 M NaOH solution?
To calculate the number of grams of NaOH in the solution, we need to use the molarity (M) and volume (V) of the solution. The equation we'll use is:
moles of NaOH = Molarity (M) x Volume (L)
First, let's convert the volume from milliliters (mL) to liters (L):
Volume (L) = 100.0 mL / 1000 = 0.1 L
Now, we can substitute the values into the equation:
moles of NaOH = 0.275 M x 0.1 L
moles of NaOH = 0.0275 moles
The molar mass of NaOH is 40.0 g/mol, so we can calculate the grams of NaOH:
grams of NaOH = moles of NaOH x molar mass
grams of NaOH = 0.0275 moles x 40.0 g/mol = 1.1 grams
Therefore, there are 1.1 grams of NaOH in 100.0 mL of a 0.275 M NaOH solution.
To calculate the number of grams of NaOH in a given solution, you need to know the solution's molarity (concentration) and volume, as well as the molecular weight of NaOH. In this case, the molarity of the NaOH solution is given as 0.275 M, and the volume is given as 100.0 mL.
To determine the number of moles of NaOH in the solution, you can use the formula:
moles = molarity × volume (in liters)
First, convert the volume from milliliters to liters by dividing it by 1000:
volume (L) = 100.0 mL ÷ 1000 = 0.100 L
Next, substitute the values into the formula:
moles = 0.275 M × 0.100 L
Calculate the moles of NaOH:
moles = 0.0275 mol
Finally, use the molecular weight of NaOH (40.0 g/mol) to convert moles to grams:
grams = moles × molecular weight
grams = 0.0275 mol × 40.0 g/mol
grams = 1.1 g
Therefore, there are 1.1 grams of NaOH in 100.0 mL of the 0.275 M NaOH solution.