i have to write chemical formulas and balance them:
nitrogen and oxyen---> nitrogen monoxide
N2+02---->2NO
nitrogen monoxide and oxygen----> nitrogen dioxide gas.
NO2+O---->NO2 (i'm not sure about this, please check)
nitrogen dioxide and water----> nitrous and nitric acids
NO2 + H20---> NO3 + H2
please check and help
The first reaction is correct as written.
2NO + O2 -> 2NO2
and
2NO2 + H2O -> HNO2 + HNO3
are the other two.
To check the chemical equations you provided, let's balance them step by step:
1. Nitrogen and oxygen → nitrogen monoxide:
N2 + O2 → 2NO
The equation is already balanced, as there are an equal number of nitrogen and oxygen atoms on both sides.
2. Nitrogen monoxide and oxygen → nitrogen dioxide:
2NO + O2 → 2NO2
This equation is balanced because there are an equal number of nitrogen, oxygen, and nitrogen dioxide molecules on both sides.
3. Nitrogen dioxide and water → nitrous and nitric acids:
3NO2 + H2O → 2HNO3 + NO
To balance this equation, we can begin by balancing the oxygen atoms on the products side. Since there are 3 oxygen atoms on the reactants side (3NO2) and 5 oxygen atoms on the products side (2HNO3 + NO), we need to add a coefficient of 5/3 in front of NO2:
5/3 NO2 + H2O → 2HNO3 + NO
Next, let's balance the nitrogen atoms. There are 2 nitrogen atoms on the product side (2HNO3) and only 1 nitrogen atom on the reactant side. We can balance this by adding a coefficient of 2 in front of NO:
5/3 NO2 + H2O → 2HNO3 + 2NO
Finally, let's balance the hydrogen atoms. There are 4 hydrogen atoms on the product side (2HNO3 + 2NO) and only 2 hydrogen atoms on the reactant side (H2O). We can balance this by adding a coefficient of 2 in front of H2O:
5/3 NO2 + 2H2O → 2HNO3 + 2NO
Now, the equation is balanced with an equal number of each element on both sides.
To check if the chemical equations are balanced, we need to ensure that the number of atoms of each element is the same on both sides of the arrow. Let's analyze each equation separately:
1. Nitrogen gas (N2) reacts with oxygen gas (O2) to form nitrogen monoxide (NO).
The equation is: N2 + O2 → 2NO
To balance this equation, we count the number of atoms on each side:
N: 2 on the left (2N), 2 on the right (2N)
O: 4 on the left (2O2), 2 on the right (2O)
The equation is already balanced because the number of atoms of each element is the same on both sides.
2. Nitrogen monoxide (NO) reacts with oxygen gas (O2) to form nitrogen dioxide gas (NO2).
The equation is: 2NO + O2 → 2NO2
To balance this equation, we count the number of atoms on each side:
N: 2 on the left (2NO), 2 on the right (2NO2)
O: 2 on the left (2NO), 2 on the right (2NO2)
The equation is balanced because the number of atoms of each element is the same on both sides.
3. Nitrogen dioxide (NO2) reacts with water (H2O) to form nitrous acid (HNO2) and nitric acid (HNO3).
The equation given is incorrect because nitrous and nitric acids are written as NO3 and H2, respectively. The correct equation is:
NO2 + H2O → HNO2 + HNO3
To balance this equation, we count the number of atoms on each side:
N: 1 on the left (NO2), 1 on the right (HNO2 and HNO3)
O: 2 on the left (NO2), 3 on the right (HNO2 and HNO3)
H: 2 on the right (HNO2), 1 on the right (HNO3)
To balance the hydrogen (H) atoms, we add a coefficient of 2 to HNO3:
NO2 + H2O → HNO2 + 2HNO3
Now the equation is balanced because the number of atoms of each element is the same on both sides.
Therefore, the balanced chemical equations are:
1. N2 + O2 → 2NO
2. 2NO + O2 → 2NO2
3. NO2 + H2O → HNO2 + 2HNO3