In Mrs Halls class of 30 students, 17 have computers at home and 20 have cassettes. If 4 students in the class have neither a computer or a cassette, how many of the 30 students have both?
To find out how many students in Mrs. Hall's class have both a computer and a cassette, we need to subtract the number of students who have neither a computer nor a cassette from the total number of students.
Given:
Total number of students in the class = 30
Number of students who have computers = 17
Number of students who have cassettes = 20
Number of students who have neither computers nor cassettes = 4
To find the number of students who have both a computer and a cassette:
Step 1: Add the number of students with computers and the number of students with cassettes:
17 + 20 = 37
Step 2: Subtract the total number of students who have neither computers nor cassettes from the result in Step 1:
37 - 4 = 33
The result is 33. However, since there are only 30 students in the class, it is not possible for 33 students to have both a computer and a cassette.
Therefore, we can conclude that there is an error in the given data or calculation. Please double-check the information provided.
To find the number of students who have both a computer and a cassette, we need to subtract the number of students who have neither from the total number of students.
Total number of students = 30
Number of students with neither a computer nor a cassette = 4
Therefore, the number of students who have both a computer and a cassette is:
Total number of students - Number of students with neither
= 30 - 4
= 26
So, 26 students in Mrs. Hall's class have both a computer and a cassette.