How many grams of NH3 can be produced from 3.26 moles of N2?

How many grams of H2 are needed to produce 13.99 g of NH3?

Follow this example. Post your work if you get stuck.

http://www.jiskha.com/science/chemistry/stoichiometry.html

To answer these questions, we need to use the balanced chemical equation for the reaction in which nitrogen gas (N2) reacts with hydrogen gas (H2) to produce ammonia gas (NH3):

N2 + 3H2 → 2NH3

Question 1: How many grams of NH3 can be produced from 3.26 moles of N2?

To determine the grams of NH3 produced, we need to use stoichiometry.

Step 1: Determine the molar ratio between N2 and NH3 from the balanced equation. As per the equation, 1 mole of N2 reacts to produce 2 moles of NH3.

Step 2: Convert moles of N2 to moles of NH3 using the molar ratio.

3.26 moles of N2 * (2 moles of NH3 / 1 mole of N2) = 6.52 moles of NH3

Step 3: Convert moles of NH3 to grams of NH3 using the molar mass of NH3. The molar mass of NH3 is 17.03 g/mol.

6.52 moles of NH3 * 17.03 g/mol = 111.9056 g

Therefore, from 3.26 moles of N2, 111.9056 grams of NH3 can be produced.

Question 2: How many grams of H2 are needed to produce 13.99 g of NH3?

To determine the grams of H2 required, we will once again use stoichiometry.

Step 1: Determine the molar ratio between H2 and NH3 from the balanced equation. As per the equation, 3 moles of H2 react to produce 2 moles of NH3.

Step 2: Convert grams of NH3 to moles of NH3 using the molar mass of NH3. The molar mass of NH3 is 17.03 g/mol.

13.99 g of NH3 * (1 mole of NH3 / 17.03 g of NH3) = 0.822 moles of NH3

Step 3: Convert moles of NH3 to moles of H2 using the molar ratio.

0.822 moles of NH3 * (3 moles of H2 / 2 moles of NH3) = 1.233 moles of H2

Step 4: Convert moles of H2 to grams of H2 using the molar mass of H2. The molar mass of H2 is 2.02 g/mol.

1.233 moles of H2 * 2.02 g/mol = 2.49286 g

Therefore, to produce 13.99 g of NH3, 2.49286 grams of H2 are needed.