Differentiate
f(x)=(x^(3)-8)^(2/3)
Please Show Work
Just use the good old chain rule.
f = (x3-8)2/3
f' = 2/3 * (x3-8)-1/3 * 3x2
f' = 2x2/(x3-8)1/3
f(x)=(x^(3)-8)^(2/3)
Please Show Work
f = (x3-8)2/3
f' = 2/3 * (x3-8)-1/3 * 3x2
f' = 2x2/(x3-8)1/3