sgr2 sinD cosD=sinD
If you're trying to solve
sqrt(2) sinD cosD = sinD
sinD(sqrt(2) cosD - 1) = 0
sinD = 0 means that D=0 + k*pi for any integer k will work.
cosD = 1/√2 means that D=2k*pi ± pi/4 will also work.
So:
47
137
227
317
Do I need to add +360n?
To solve this equation, you can use basic trigonometric identities. Let's break it down step by step:
Given: sgr2 sinD cosD = sinD
Step 1: Divide both sides of the equation by sinD:
sgr2 cosD = 1
Step 2: Divide both sides of the equation by cosD:
sgr2 = 1 / cosD
Step 3: Take the square root of both sides of the equation:
sgr = sqrt(1 / cosD)
In this step, it's important to note that we take the positive square root because cosine values are always positive.
Step 4: Simplify the expression on the right-hand side:
sgr = sqrt(1) / sqrt(cosD) (Using the property sqrt(a/b) = sqrt(a) / sqrt(b))
sgr = 1 / sqrt(cosD) (Since sqrt(1) = 1)
So, the solution to the equation sgr2 sinD cosD = sinD is sgr = 1 / sqrt(cosD).