1. Questions

algebra

Find value of
log (base 8)log (base 2) log (base 3)log (base 3) (27)^3

I endedup with 1.000063462 which was wrong

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
TC

  1. If you want to use a calculator to evaluate the above expression, you will need to understand the above expression is evaluated from right to left, so appropriate sets of parentheses must be inserted.

    In fact, the above expression can be evaluated mentally to a simple fraction.

    log (base 8)log (base 2) log (base 3)log (base 3) (27)^3
    should be written as follows (square brackets have been inserted):
    log (base 8) [log (base 2) [ log (base 3) [ log (base 3) (27)^3 ] ] ]
    Start evaluating from the innermost set of brackets outwards.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    MathMate

  2. zero.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    Anonymous

Respond to this Question

First Name

Your Response

Similar Questions

  1. Logarithms

    CONDENSE INTO THE LOG OF A SINGLE QUANTITY: (1) Base 7 2/3 log( z - 2 ) (2) 2 ln8 + 5 ln( z - 4 ) (3) Base 4 1/2 [ log( x + 1 ) + 2 log( x - 1 ) ] + 6 logx

  2. math

    Given that 2 log base2 (x+15) - log base2 x = 6 1.Show that x^2 -34x +225 = 0 2. Hence or otherwise solve the equation 2 log base 2 (x+15) - log base 2 x =6

  3. Biochemistry

    Calculate how you would make 0.5L of a 0.5M (500mM) acetate buffer at a pH of 4.7. Available is sodium acetate and glacial acetic acid. pH=4.7 pKa of acetic acid=4.76 Not sure if I did this next part right: 4.7=4.76 + log

  4. math

    If log (base b) 3 = 1.099 and log (base b) 6 = 1.792, find log (base b) 18 = ???

  1. chemistry

    Q: Calculate the pH of a solution that is 0.56 M HC3H5O3 and 1.28 M NaC3H5O3. I used the H-H equation for this and got this so far: HC3H5O3 acid NaC3H5O3 base pH = pKa + log([NaC3H5O3]/[HC3H5O3]) = -log(Ka of HC3H5O3) +

  2. College Algebra

    Solve the logarithmic equation. Express your solutions in exact form only. Please show all of your work. log base 6 (64x^3+1)-log base 6 (4x+1)=1

  3. Math

    The problem I have to solve is log with base 2 ^6 multiply by log base 6 ^ 8. I use the change of base formula and got log6/log2 * log8/log6 Which become log6/log2 * log2()^3/ log 6 I'm stuck here thanks.

  4. math(Please help)

    1) use the properties of logarithms to simplify the logarithmic expression. log base 10 (9/300) log - log 300 log 9 = 2 log 3 log 300 = log 3 + log 100 = log 3+2 I just do not know how to put these together now!

  1. Algebra 2

    Use the laws of logarithms to condense the following expressions. log base 5 of 6 - log base 5 of x

  2. precalc

    Suppose that u=log(2) and v=log(5). Find possible formulas for the following expressions in terms of u and/or v. Your answers should NOT involve any log's. a) log(0.4)= b) log(0.08)= c) log(2500)=

  3. Econ math/logarithms

    If log with base b (2)=0.39 and log with base b (3)=0.61 evaluate the following. log with base b (8). Simplify your answer. How to start? I thought I am supposed to write log base b 2^3 but I don't seem to get an answer that would

  4. Algebra 2

    Express as a single logarithm. 1/2 log base b of (x-2)- log base b of y + (3 log base b of z) = log base 6 of (x-2)^1/2

View more similar questions or ask a new question.