what is the molarity of an aqueous solution that is 6.75% glucose by mass? Assume a density of 1.03 g/ml

0.386M

6.75% w/w means 6.75g glucose/100 g soln

Convert 6.75 g glucose t moles. moles = grams/molar mass.
Convert 100 g soln to volume using density.
Then M = moles/L.

To find the molarity of the aqueous solution, we first need to determine the mass of glucose present in the solution.

Step 1: Calculate the mass of the solution:
Assume we have 100 grams of the solution (since it is a percentage by mass). Given the density of the solution, 1.03 g/ml, we can find the volume of the solution:
Volume of the solution = Mass of the solution / Density = 100 g / (1.03 g/ml) ≈ 97.09 ml

Step 2: Calculate the mass of glucose in the solution:
Given that the solution is 6.75% glucose by mass, we can calculate the mass of glucose present:
Mass of glucose = (6.75/100) × 100 g = 6.75 g

Step 3: Convert the mass of glucose to moles:
To convert the mass of glucose to moles, we need to know the molar mass of glucose. The molecular formula of glucose is C6H12O6, so the molar mass can be calculated as follows:
Molar mass of glucose = (6 * atomic mass of carbon) + (12 * atomic mass of hydrogen) + (6 * atomic mass of oxygen)
= (6 * 12.01 g/mol) + (12 * 1.01 g/mol) + (6 * 16.00 g/mol)
≈ 180.18 g/mol

Number of moles of glucose = Mass of glucose / Molar mass of glucose
= 6.75 g / 180.18 g/mol
≈ 0.0374 mol

Step 4: Calculate the volume of the solution in liters:
To find the volume of the solution in liters, divide the volume (in milliliters) by 1000:
Volume of the solution = 97.09 ml / 1000
≈ 0.09709 L

Step 5: Calculate the molarity:
The molarity (M) is defined as moles of solute per liter of solution.
Molarity (M) = Number of moles of solute / Volume of solution in liters
= 0.0374 mol / 0.09709 L
≈ 0.385 M

Therefore, the molarity of the aqueous solution is approximately 0.385 M.

To determine the molarity of the aqueous solution, we first need to calculate the mass of glucose present in the solution.

Step 1: Calculate the mass of the solution.
Given that the density of the solution is 1.03 g/ml, we can assume we have 100 g of solution because 1 ml of water is equivalent to 1 g.

Step 2: Calculate the mass of glucose in the solution.
Since the solution is 6.75% glucose by mass, we multiply the mass of the solution by the percentage of glucose:
100 g x 6.75% = 6.75 g

Step 3: Calculate the molarity.
To find the molarity of the solution, we need to know the molar mass of glucose. The molar mass of glucose (C6H12O6) is approximately 180.16 g/mol.

Next, we calculate the number of moles of glucose in the solution by dividing the mass of glucose by its molar mass:
6.75 g / 180.16 g/mol = 0.03736 mol

Finally, we calculate the molarity by dividing the number of moles of solute (glucose) by the volume of the solution in liters:
Molarity = 0.03736 mol / 0.1 L = 0.3736 M

Therefore, the molarity of this aqueous glucose solution is 0.3736 M.