Could someone please check these.
For ellipse:
(x-2)^2/49 + (y+1)^2/25 = 1
1.What is the major axis in equation form of this ellipse?
The major axis is the x axis, so if the major axis is horizontal, the equation is based off the minor axis so the answer is y= -1 for the major axis equation, correct?
2. What is the transverse axis of the hyperbole? Answer would be y = 5or if they're not asking for equation, THEN i SAY x= -3??? Not sure??
The major axis does not have an equation, as such. It is just the length of the larger of the two axes. The major axis is 14, extending from one side of the ellipse to the other. It does happen to lie along the line y = -1, as you say, but the line is not the axis.
As for the hyperbola, since you don't cite an equation, it's hard to say. The transverse axis contains the two foci.
So, if you have
x^2/25 - y^2/49 = 1, then the transverse axis is horizontal, and lies along the line y = 0. The transverse axis is the line segment between the two foci, of length 10.
b/3 + 6=82
x-5x=2(-3x+4)
To find the major axis of an ellipse, you need to examine the equation and determine whether the major axis is horizontal or vertical. In the given equation:
(x-2)^2/49 + (y+1)^2/25 = 1
The denominators under (x-2)^2 and (y+1)^2 indicate that the major axis is generated by the y-term, which means the major axis of this ellipse is vertical.
To represent the major axis equation, you need to consider the central point of the ellipse, which is (2, -1). Since the major axis is vertical, the equation of the major axis can be written as:
x = 2
As for the second part of your question regarding the transverse axis of the hyperbola, there seems to be a misunderstanding. The given equation represents an ellipse, not a hyperbola. Therefore, it is not necessary to determine the transverse axis for this equation.