At the end of a race a runner decelerates from a velocity of 7.00 m/s at a rate of 0.500 m/s2.
(a) How far does she travel in the next 14.0 s in meters?
distance= vi*14-1/2 .5 14^2
wait what??? i don't understand the equation??
vi times 14 second
plus
1/2 times 1/2 times 14 times 14
its wrong....i got 147 for what you said but it doesnt work
Exactly. You can't just throw equations out there and expect people to understand. That's the reason why we're here, is because we DON'T understand. SO, can you please simplify this problem a little more?
To find the distance traveled by the runner, we need to use the equation of motion:
distance = initial velocity * time + (1/2) * acceleration * time^2
Given:
Initial velocity (u) = 7.00 m/s
Acceleration (a) = -0.500 m/s^2 (negative because deceleration)
Time (t) = 14.0 s
Substituting the values into the equation of motion:
distance = 7.00 m/s * 14.0 s + (1/2) * (-0.500 m/s^2) * (14.0 s)^2
Simplifying:
distance = 98.00 m + (1/2) * (-0.500 m/s^2) * 196.00 s^2
distance = 98.00 m + (-0.250 m/s^2) * 196.00 s^2
distance = 98.00 m + (-0.250) * 196.00 m
distance = 98.00 m - 49.00 m
distance = 49.00 m
Therefore, the runner travels a distance of 49.00 meters in the next 14.0 seconds.