The yearly attendance at a local movie theater is 82,000 and grows continuously at a rate of 5.1% each year. What is the approximate attendance at the movie theater in ten years?

attendance = 82000( e^(.051*10) = 136554

Is it right?

Just took the Unit 1 Saving Lesson 6 Growth and Decay ADQUANR A quiz. Here are the answers:

1. 25
2. a_n=a_n-1+(2n-3) (fourth choice)
3. 35,568.95
4. 12,374.19
5. 136,554
6. 30,824

I didn't get 100% but i got to see which answers are right. These are right.

Connexus update

1. 49
2. an=an-1+(2n-3)
3. 35568.95
4. 6675.78
5. 136554
6. 30824

To find the approximate attendance at the movie theater in ten years, we need to use the formula for exponential growth:

A = P(1 + r)^t

Where:
A = attendance after t years
P = initial attendance
r = growth rate per year (as a decimal)
t = number of years

In this case, the initial attendance (P) is 82,000, the growth rate (r) is 5.1% or 0.051, and the number of years (t) is 10.

So, substituting these values into the formula, we get:

A = 82,000(1 + 0.051)^10

Now, we can calculate the approximate attendance at the movie theater in ten years.