If there are exactly 5 times as many children as adults at a show, which of the following cannot be the number of people at the show?

There is nothing "following".

The total number, whatever it is, must be evenly divisible by 6.

To determine which option cannot be the number of people at the show, we need to find a number of adults that is not compatible with the given condition.

Let's assume the number of adults at the show is 'A'. According to the given information, there are exactly 5 times as many children as adults. Therefore, the number of children would be 5A.

The total number of people at the show would be the sum of adults and children, which can be represented as: A + 5A = 6A.

To find the potential options that cannot be the number of people at the show, we need to look for an option that cannot be expressed as 6A, where A is a positive integer (number of adults).

For example, 30 can be expressed as 6 x 5 (A = 5), so it could be the number of people at the show. However, 27 cannot be expressed as 6A, where A is an integer. Therefore, we can conclude that the option 27 cannot be the number of people at the show.

In summary, the number of people at the show cannot be 27.