If a sample of pure hydrogen gas is ignited very carefully, the hydrogen burns gently, combining with the oxygen gas of the air to form water vapor. Write the unbalanced chemical equation for this reaction.
H2(g) + O2(g) --> H2O(l) unbalanced.
2H2(g) + O2(g) ==> 2H2O(l) balanced.
H2(g)+O2(g)-->H2O(g)
2h+o2=h2o2
Well, isn't hydrogen just a gas that loves getting "H2O-ver" its head? Here's the unbalanced equation for this fiery encounter:
H2 + O2 → H2O
To write the unbalanced chemical equation for the combustion of hydrogen gas (H₂) with oxygen gas (O₂) to form water vapor (H₂O), we need to consider the reactants and the products involved.
The reaction can be represented as follows:
Hydrogen gas (H₂) + Oxygen gas (O₂) → Water vapor (H₂O)
However, this equation is unbalanced because the number of atoms on both sides of the equation is not equal. To balance the equation, we need to make sure that the number of atoms of each element is the same on both sides.
Balanced equation:
2 H₂ + O₂ → 2 H₂O
In the balanced equation, we have two hydrogen gas molecules reacting with one oxygen gas molecule to yield two water vapor molecules.
To balance the equation, we multiply the hydrogen gas molecule by 2 on the left side to match the number of hydrogen atoms on the right side. Similarly, the oxygen gas molecule remains as it is on the left side and we have the same number of oxygen atoms on both sides. Finally, we have two water vapor molecules on the right side to match the number of hydrogen atoms on the left side.
Remember, balancing chemical equations is important to ensure that the law of conservation of mass is upheld, meaning that the number of atoms of each element remains unchanged during a chemical reaction.