find the force of gravity between 74.0kg physics students that are sitting 85.0 cm apart

F = G M1*M2/R^2

Use 0.85 m for R

G = 6.67*10^-11 N*m^2/kg^2

force=G(m1m2/r^2) G=6.673x10^-11

To find the force of gravity between two objects, we can use Newton's law of universal gravitation:

F = (G * m1 * m2) / r^2

Where:
F is the force of gravity
G is the gravitational constant (6.67430 x 10^-11 N*m^2/kg^2)
m1 and m2 are the masses of the two objects
r is the distance between the centers of the two objects

In this case, we have two physics students with a mass of 74.0 kg each and sitting 85.0 cm (or 0.85 m) apart.

Plugging these values into the formula, we get:

F = (6.67430 x 10^-11 N*m^2/kg^2) * (74.0 kg) * (74.0 kg) / (0.85 m)^2

Calculating this expression step by step:

Step 1: Calculate the square of the distance

r^2 = (0.85 m)^2 = 0.7225 m^2

Step 2: Calculate the multiplication of masses and the gravitational constant

(6.67430 x 10^-11 N*m^2/kg^2) * (74.0 kg) * (74.0 kg) = 3.6378885 x 10^-8 N*m^2/kg

Step 3: Divide the result from Step 2 by the square of the distance

F = (3.6378885 x 10^-8 N*m^2/kg) / (0.7225 m^2)

Step 4: Calculate the final result

F ≈ 5.036 x 10^-8 N

Therefore, the force of gravity between the two physics students is approximately 5.036 x 10^-8 N.

To find the force of gravity between the two physics students, we can use Newton's law of universal gravitation, which states that the force of gravity between two objects is determined by their masses and the distance between them. The formula is:

F = G * (m1 * m2) / d^2

Where:
F is the force of gravity
G is the gravitational constant (6.67430 × 10^-11 N m^2/kg^2)
m1 and m2 are the masses of the two objects
d is the distance between the two objects (in this case, the students' distance)

In this case, the mass of each student is given as 74.0 kg, and the students are sitting 85.0 cm (or 0.85 m) apart.

Plugging the values into the formula, we get:

F = (6.67430 × 10^-11 N m^2/kg^2) * (74.0 kg * 74.0 kg) / (0.85 m)^2

Calculating this, the force of gravity between the two physics students is:

F ≈ 3.00 × 10^-9 N

Therefore, the force of gravity between the 74.0 kg physics students sitting 85.0 cm apart is approximately 3.00 × 10^-9 N.