if x moles of PbCl2(s) dissolve in 1.00L of water, how many moles of Pb2+(aq) are produced? how many Cl- produced?

PbCl2(s) ==> Pb^2+(aq) + 2Cl^-(aq)

....x........x...........2x

To determine the number of moles of Pb2+ and Cl- produced when x moles of PbCl2(s) dissolve in 1.00L of water, we need to understand the stoichiometry of the chemical reaction.

The balanced chemical equation for the dissociation of PbCl2(s) in water is:

PbCl2(s) -> Pb2+(aq) + 2Cl-(aq)

From the equation, we can see that for every 1 mole of PbCl2(s) that dissolves, 1 mole of Pb2+(aq) and 2 moles of Cl-(aq) are produced.

Therefore, if x moles of PbCl2(s) dissolve, the number of moles of Pb2+(aq) produced is also x. Similarly, the number of moles of Cl-(aq) produced is 2x.

Therefore, the answer to the question is:
- The number of moles of Pb2+(aq) produced is x moles
- The number of moles of Cl-(aq) produced is 2x moles