A torque of 0.13 N*m is applied to an egg beater. If the egg beater starts at rest, what is its angular momentum after 0.50 s?
To find the angular momentum of the egg beater after 0.50 s, we need to use the formula:
Angular momentum (L) = Moment of inertia (I) * Angular velocity (ω)
However, we need to find the angular velocity first. Torque (τ) is given by:
τ = I * α
Where α represents the angular acceleration. Rearranging the equation, we get:
α = τ / I
Since the egg beater starts from rest, we can assume that its initial angular velocity is zero (ω₀ = 0). The final angular velocity (ω) can be found using the following equation:
ω = ω₀ + α * t
Where t represents the time duration. Now we can substitute the given values into the equations to calculate the answer step by step:
1. First, calculate the angular acceleration (α):
α = τ / I = 0.13 N*m / I
2. Then, calculate the angular velocity (ω):
ω = ω₀ + α * t = 0 + (0.13 N*m / I) * 0.50 s = 0.065 N*m/s / I
3. Finally, calculate the angular momentum (L):
L = I * ω
Remember, we don't have information about the moment of inertia (I) of the egg beater, so we can't calculate the exact value of the angular momentum. We only know that the angular momentum (L) is equal to I * (0.065 N*m/s / I).
Please provide the moment of inertia (I) of the egg beater to calculate the final answer.