In a city with no cars of mixed color, 30% of the cars on the road are brown. Forty percent are either brown or green, and 10% are white.
a.) What is the probability that a randomly selected car is green?
b.) What is the probability that a randomly selected car is not brown, green, or white?
Thanks a bunch for whoever can help!?
How many cars were there altogether?
It doesn't say how many cars in total there were. Im guessing that in total these cars added up to 100%.
a.)1/5
b.)1/4
Is there anyway that you can show me how you got that so I can understand a little better? Thanks!
a.)40% of cars are either brown or green. Divide that by two since there are two colors. You get 20. Put that over 100=20/100. Reduce it to 2/10 which reduces to 1/5.
b.)Add all the percents together to get 80%. Subtract it from 100. 100-80=20. 20/100=1/5. So the actual answer to b is 1/5. Sorry, my mistake. :P
Thanks a bunch!
No problem.(:
What about the undefined remaining 20%?
30% + 40% + 10% = only 80%
She DID do that.
To calculate the probabilities, we first need to determine the total number of car colors in the city based on the given information.
Let's assume that the total number of cars in the city is 100 (for ease of calculation).
a.) To find the probability that a randomly selected car is green, we need to determine the percentage of green cars among all the cars.
Given that 40% of the cars are either brown or green, and 30% of the cars are brown, we can find the percentage of green cars as follows:
Percentage of green cars = Total percentage of brown and green cars - Percentage of brown cars
= 40% - 30%
= 10%
Now, we know that 10% of the cars are green. Therefore, the probability of selecting a green car randomly would be 10/100 = 0.1 or 10%.
b.) To find the probability that a randomly selected car is not brown, green, or white, we need to determine the percentage of cars that fall into those categories.
Given that 30% of the cars are brown, and 10% are white, we can find the percentage of cars that are not brown or white as follows:
Percentage of cars that are not brown or white = 100% - Percentage of brown cars - Percentage of white cars
= 100% - 30% - 10%
= 60%
Now, we know that 60% of the cars are not brown or white. Therefore, the probability of selecting a car that is not brown, green, or white randomly would be 60/100 = 0.6 or 60%.
In conclusion:
a.) The probability that a randomly selected car is green is 10% or 0.1.
b.) The probability that a randomly selected car is not brown, green, or white is 60% or 0.6.