leo saw 8 times more snails than starfish at the aquarium. he saw 10 more sea horses than starfish. leo saw 70 animals. how many of each did he see?
Let x = starfish, the 8x = snails and x+10 = sea horses.
x + 8x + x + 10 = 70
Solve for x and then the other terms.
8+8+8
DIE
To find the number of each animal that Leo saw, we can set up a system of equations based on the information provided.
Let's assume the number of starfish that Leo saw is 'x'.
According to the problem statement, Leo saw 8 times more snails than starfish. Therefore, the number of snails he saw would be 8 times 'x', which is 8x.
Leo also saw 10 more seahorses than starfish, so the number of seahorses he saw would be 'x + 10'.
We know that Leo saw a total of 70 animals. So, the sum of the three types of animals would equal 70:
x + 8x + (x + 10) = 70
Simplifying the equation:
10x + 10 = 70
Subtracting 10 from both sides:
10x = 60
Dividing both sides by 10:
x = 6
So, Leo saw 6 starfish, 8 times more snails (8 * 6 = 48 snails), and 10 more seahorses (6 + 10 = 16 seahorses).
Therefore, Leo saw 6 starfish, 48 snails, and 16 seahorses.