a charge of + 2x10-7c is 10cm from a charge of -6x10-6c find magnitude and direction of force on each charge

Use Coulomb's law.

I'm confused

To find the magnitude and direction of the force on each charge, we can use the formula for the electric force between two charges:

F = k(|q1||q2|) / r^2

where
- F is the force between the charges,
- k is the electrostatic constant (k = 8.99 × 10^9 Nm^2/C^2),
- |q1| and |q2| are the magnitudes of the charges, and
- r is the distance between the charges.

Let's calculate the forces on the two charges:

1. Force on the charge of +2x10^(-7) C:
q1 = +2x10^(-7) C
q2 = -6x10^(-6) C
r = 10 cm = 0.1 m

Plugging the values into the formula:
F = (8.99 × 10^9 Nm^2/C^2) × (|2x10^(-7) C||-6x10^(-6) C|) / (0.1 m)^2

F = (8.99 × 10^9 Nm^2/C^2) × (2x10^(-7) C) × (6x10^(-6) C) / (0.1 m)^2
F = 107.88 N

Therefore, the magnitude of the force on the charge of +2x10^(-7) C is 107.88 N.

2. Force on the charge of -6x10^(-6) C:
q1 = -6x10^(-6) C
q2 = +2x10^(-7) C
r = 10 cm = 0.1 m

Plugging the values into the formula:
F = (8.99 × 10^9 Nm^2/C^2) × (|-6x10^(-6) C||2x10^(-7) C|) / (0.1 m)^2

F = (8.99 × 10^9 Nm^2/C^2) × (6x10^(-6) C) × (2x10^(-7) C) / (0.1 m)^2
F = 107.88 N

Therefore, the magnitude of the force on the charge of -6x10^(-6) C is 107.88 N.

Both charges experience a force of 107.88 N. The direction of the force on the charge of +2x10^(-7) C is repulsive (away from the other charge) because the charges have opposite signs. The direction of the force on the charge of -6x10^(-6) C is attractive (towards the other charge) because the charges have opposite signs.

To find the magnitude and direction of the force on each charge, we can use Coulomb's Law. Coulomb's Law states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's Law is:

F = (k * |q1 * q2|) / r^2

Where:
- F is the magnitude of the force
- k is the electrostatic constant (9 x 10^9 N*m²/C²)
- q1 and q2 are the charges of the two point charges
- r is the distance between the charges

Let's calculate the magnitude and direction of the force on each charge:

1. Magnitude and direction of force on charge +2x10^-7 C due to charge -6x10^-6 C:
- q1 (charge 1) = +2x10^-7 C
- q2 (charge 2) = -6x10^-6 C
- r (distance) = 10 cm = 0.1 m

Plugging these values into the Coulomb's Law formula:
F = (9 x 10^9 N*m²/C²) * |(+2x10^-7 C) * (-6x10^-6 C)| / (0.1 m)^2
F = (9 x 10^9 N*m²/C²) * (12 x 10^-13 C²) / (0.01 m²)
F = 108 x 10^-4 N

The magnitude of the force on charge +2x10^-7 C due to charge -6x10^-6 C is 108 x 10^-4 N. Since both charges are opposite in sign, the force will be attractive.

2. Magnitude and direction of force on charge -6x10^-6 C due to charge +2x10^-7 C:
- q1 (charge 1) = -6x10^-6 C
- q2 (charge 2) = +2x10^-7 C
- r (distance) = 10 cm = 0.1 m

Plugging these values into the Coulomb's Law formula:
F = (9 x 10^9 N*m²/C²) * |(-6x10^-6 C) * (+2x10^-7 C)| / (0.1 m)^2
F = (9 x 10^9 N*m²/C²) * (12 x 10^-13 C²) / (0.01 m²)
F = 108 x 10^-4 N

The magnitude of the force on charge -6x10^-6 C due to charge +2x10^-7 C is also 108 x 10^-4 N. Since both charges are opposite in sign, the force will be attractive.

To summarize:
- The magnitude of the force on the +2x10^-7 C charge is 108 x 10^-4 N (attractive).
- The magnitude of the force on the -6x10^-6 C charge is 108 x 10^-4 N (attractive).