6. You read in a book about bridge that the probability that each of the four players is dealt exactly one ace is about 0.11. This means that
A.
in every 100 bridge deals, each player has one ace exactly 11 times.
B.
in one million bridge deals, the number of deals on which each player has one ace will scarcely be within ±100 of 110,000.
C.
in a very large number of bridge deals, the percent of deals on which each player has one ace will be very close to 11%.
D.
in a very large number of bridge deals, the average number of aces in a hand will be very close to 0.11.
7.If the knowledge that an event A has occurred implies that a second event B cannot occur, the events A and B are said to be
A.
independent.
B.
disjoint.
C.
mutually exhaustive.
D.
the sample space.
E.
complementary.
8. If you draw an M&M candy at random from a bag of the candies, the candy you draw will have one of six colors. The probability of drawing each color depends on the proportion of each color among all candies made. Assume that the table below gives the probability that a randomly chosen M&M has each color.
Color Brown Red Yellow Green Orange Tan
Probability .3 .3 ? .1 .1 .1
R-3 Ref 6-2
The probability of drawing a yellow candy is
A.
0.
B.
.1.
C.
.2.
D.
.3.
E.
impossible to determine from the information given.
9. Suppose we roll a red die and a green die. Let A be the event that the number of spots showing on the red die is three or less and B be the event that the number of spots showing on the green die is more than three.
R-4 Ref 6-6
P(A B) =
A.
1.
B.
5/6.
C.
2/3.
D.
1/4.
E.
1/6.
10. Suppose we roll a red die and a green die. Let A be the event that the number of spots showing on the red die is three or less and B be the event that the number of spots showing on the green die is more than three.
R-4 Ref 6-6
P(A B) =
A.
1/6.
B.
1/4.
C.
1/3.
D.
5/6.
E.
none of these.
11. Suppose we roll a red die and a green die. Let A be the event that the number of spots showing on the red die is three or less and B be the event that the number of spots showing on the green die is more than three.
R-4 Ref 6-6
The events A and B are
A.
disjoint.
B.
conditional.
C.
independent.
D.
reciprocals.
E.
complementary.
dear,
PsyDAG
i asked for help because i didn't know how to do it not because i didn't want to do the work daaaaaaa!!!!
6. C. in a very large number of bridge deals, the percent of deals on which each player has one ace will be very close to 11%.
7. B. disjoint.
8. C. .2.
9. B. 5/6.
10. A. 1/6.
11. C. independent.
6. The probability that each of the four players is dealt exactly one ace is about 0.11. This means that the correct option is C. In a very large number of bridge deals, the percent of deals on which each player has one ace will be very close to 11%. To understand this, we need to know how to calculate probability. Probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. In this case, the favorable outcome is each player being dealt exactly one ace, and the total number of possible outcomes is the total number of bridge deals. By performing many bridge deals, we can calculate the percentage of deals where each player has one ace, which will converge to approximately 11%.
7. The events A and B are said to be disjoint if the knowledge that event A has occurred means that event B cannot occur. The correct option is B. Disjoint events are events that cannot happen at the same time. This means that if event A has occurred, event B cannot occur and vice versa. For example, if event A is "rolling an even number on a fair die" and event B is "rolling an odd number on a fair die," these events are disjoint since it is impossible to roll both an even and odd number on the same roll.
8. The probability of drawing a yellow candy from a bag of M&M candies can be determined from the given information. The correct option is C. The table provides the probabilities of each color, but the probability of yellow is missing. To find the probability of drawing a yellow candy, we need to subtract the probabilities of all other colors from 1, since the sum of all probabilities should equal 1. Therefore, the probability of drawing a yellow candy is 1 - (0.3 + 0.3 + 0.1 + 0.1 + 0.1) = 0.2.
9. The probability of the event A union B (A ∪ B) can be calculated using set notation. The correct option is C. The event A is defined as the number of spots showing on the red die being three or less, and the event B is defined as the number of spots showing on the green die being more than three. To find the probability of A ∪ B, we need to find the probability of either event A occurring, event B occurring, or both occurring. Since any roll of the dice will satisfy either event A or event B (or both), the probability of A ∪ B is equal to 1.
10. The probability of the event A intersection B (A ∩ B) can also be calculated using set notation. The correct option is E. The event A is defined as the number of spots showing on the red die being three or less, and the event B is defined as the number of spots showing on the green die being more than three. To find the probability of A ∩ B, we need to find the probability of both event A and event B occurring simultaneously. Since the number of spots showing on the red die cannot be both three or less and more than three at the same time, the probability of A ∩ B is 0.
11. The events A and B are mutually exclusive or disjoint if they cannot occur at the same time. And, the events A and B are said to be independent if the occurrence of one event does not affect the probability of the occurrence of the other event. The correct option is A. The events A and B in this scenario are disjoint since the number of spots showing on the red die cannot be both three or less and more than three at the same time. Therefore, the correct answer is that the events A and B are disjoint.