A force of -9000 N is used to stop a 1500kg car traveling at 20 m/s. What braking distance is needed to bring the car to a halt?
a = F / m = -9000 / 1500 = -6m/s^2.
d = (Vf^2 - Vo^2) / 2a,
d = (0 - (20)^2) / -12 = 33.33m.
Oh boy, we've got some physics going on here! So, let's calculate the braking distance for this car.
First, we need to find the acceleration of the car. We can use Newton's second law of motion, which states that force equals mass times acceleration (F = m * a).
In this case, the force is -9000 N (negative sign indicates deceleration), and the mass of the car is 1500 kg. Rearranging the equation, we get:
a = F / m
= -9000 N / 1500 kg
= -6 m/s²
Now, we can use another kinematic equation to find the braking distance. The equation is v² = u² + 2aS, where v is the final velocity, u is the initial velocity, a is the acceleration, and S is the distance.
In this case, the final velocity v is 0 m/s because we want to bring the car to a halt. The initial velocity u is 20 m/s, and the acceleration a is -6 m/s². Rearranging the equation, we find:
S = (v² - u²) / (2a)
= (0 - (20)²) / (2 * -6)
= -400 / -12
= 33.33 meters
So, my friend, the braking distance needed to bring the car to a halt is approximately 33.33 meters. Just make sure you don't brake too hard, or else the clown in the backseat might start juggling!
To find the braking distance needed to bring the car to a halt, we can use the formula:
Braking distance = (initial velocity ^ 2) / (2 * acceleration)
First, let's calculate the acceleration of the car using the given force and mass:
acceleration = force / mass
acceleration = -9000 N / 1500 kg
acceleration = -6 m/s²
Now, we can plug in the values into the formula:
Braking distance = (20 m/s)^2 / (2 * -6 m/s²)
Braking distance = 400 m²/s² / (-12 m/s²)
Braking distance = -33.33 m²/s²
However, the negative sign indicates that the car is slowing down, so we take the absolute value:
Braking distance = 33.33 m²/s²
Therefore, the braking distance needed to bring the car to a halt is approximately 33.33 meters.
To find the braking distance needed to bring the car to a halt, we can use the equations of motion.
First, we need to determine the acceleration of the car. Newton's second law of motion states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. So, we can use the formula:
Force = mass x acceleration
Rearranging the formula to solve for acceleration:
Acceleration = Force / Mass
Now, we can substitute the given values into the equation:
Acceleration = -9000 N / 1500 kg
Acceleration = -6 m/s^2
Since the car is coming to a halt, its final velocity will be zero (0 m/s). We are given the initial velocity (20 m/s), and we need to find the braking distance.
We can use the following equation of motion to determine the braking distance:
v^2 = u^2 + 2as
Where:
v = final velocity (0 m/s)
u = initial velocity (20 m/s)
a = acceleration (-6 m/s^2)
s = braking distance (what we want to find)
Substituting the known values into the equation:
0^2 = 20^2 + 2*(-6)*s
0 = 400 - 12s
12s = 400
s = 400 / 12
Therefore, the braking distance needed to bring the car to a halt is approximately 33.33 meters.
Kinetic energy of car before breaking:
Wk = mass * velocity^2/2
Wk = 1500 * 20^2/2
The work done by the car to transfer kinetic energy to frictional heat:
W(friction) = Force * Distance
-9000n * Distance
As no energy can be lost only transformed, we can write: 1500 * 20^2 /2 = -9000n * distance
solving for distance we get:
Distance = 1500 * 20^2/2 * -9000
Distance = -33,333
As distance can't be negative and is a scalar quantity we can write 33.333m