Find the smallest positive value of x which satisfies 1.400cos(1.000x)
Give answer in four decimal places for accuracy.
first you need to find the smallest positive value of x which satisfies 1.400cos(1.000x)
this should help
I got 1.5708, but it's wrong
its magic
To find the smallest positive value of x that satisfies the equation 1.400cos(1.000x), we can start by understanding the graph of the cosine function.
The cosine function oscillates between -1 and +1 over a period of 2π. This means that the smallest positive value of x that satisfies the equation will be when the cosine function reaches its minimum value of -1.
In order to find this value, we need to determine the phase shift, or the horizontal displacement of the cosine function. The general equation for the cosine function is:
y = A * cos(Bx - C)
In our equation, 1.400cos(1.000x), the amplitude (A) is 1.400. The coefficient of x, B, is 1.000. However, we don't have any value for C, which indicates that there is no phase shift.
Since there is no phase shift, the minimum value of the cosine function occurs when the argument of the cosine function, 1.000x, is equal to 0 radians. This means:
1.000x = 0
Solving for x:
x = 0
Therefore, the smallest positive value of x that satisfies the equation 1.400cos(1.000x) is 0.
No matter the value of x, the cosine of 0 radians is always equal to 1, and multiplying it by 1.400 gives us the value 1.400.
Therefore, the smallest positive value of x is 0, and the answer is 1.400 written to four decimal places.