A horizontal rod with a length of 0.250 is mounted on a balance and carries a current. At the location of the rod a uniform horizontal magnetic field has a magnitude of 6.70×10−2 and direction perpendicular to the rod. The magnetic force on the rod is measured by the balance and is found to be 0.190 . What is the current?
You must provide dimensions with your numbers.
To find the current, we can use the formula for the magnetic force on a current-carrying wire, which is given by:
F = BIL
Where:
F is the magnetic force
B is the magnitude of the magnetic field
I is the current
L is the length of the wire
In this case, we are given:
B = 6.70×10^(-2) (magnitude of the magnetic field)
L = 0.250 (length of the rod)
F = 0.190 (measured magnetic force)
Rearranging the formula, we can solve for the current (I):
I = F / (BL)
Plugging in the values, we get:
I = 0.190 / (6.70×10^(-2) * 0.250)
Now, let's calculate it:
I = 0.190 / (0.066875)
I ≈ 2.84 Amperes
Therefore, the current flowing through the rod is approximately 2.84 Amperes.