what is the molarity of a solution prepared by dissolving 2.24 grams of NaOH in enough deionized water to obtain 500.0ml of solution?The molar mass of NaOH is 40.0g
To find the molarity of a solution, you need to know the number of moles of solute (NaOH) and the volume of the solution.
Step 1: Calculate the number of moles of NaOH:
Using the given mass of NaOH (2.24 grams) and the molar mass of NaOH (40.0 g/mol), you can calculate the number of moles by dividing the mass by the molar mass.
Number of moles = mass (g) / molar mass (g/mol)
Number of moles = 2.24 g / 40.0 g/mol
Step 2: Calculate the molarity using the number of moles and the volume of the solution.
Molarity (M) = Number of moles / Volume (L)
Since the given volume is in milliliters (ml), you need to convert it to liters (L) by dividing by 1000.
Volume (L) = 500.0 ml / 1000
Now, you can substitute these values into the equation:
Molarity (M) = (2.24 g / 40.0 g/mol) / (500.0 ml / 1000)
Molarity (M) = 0.056 mol / 0.500 L
Calculating this expression will give you the molarity of the solution.
To find the molarity of a solution, you need to know the number of moles of solute (NaOH) and the volume of the solution.
First, calculate the number of moles of NaOH using its molar mass and given mass:
Number of moles = Mass / Molar mass
Mass = 2.24 grams
Molar mass of NaOH = 40.0 grams/mole
Number of moles = 2.24 g / 40.0 g/mol = 0.056 moles
Next, convert the volume of the solution to liters:
Volume of solution = 500.0 mL = 500.0 cm³ = 500.0 cm³ * (1 mL / 1 cm³) * (1 L / 1000 mL) = 0.500 L
Finally, calculate the molarity using the moles of NaOH and the volume of the solution:
Molarity = Number of moles / Volume of solution
Molarity = 0.056 mol / 0.500 L = 0.112 M
Therefore, the molarity of the solution prepared is 0.112 M.
Molarity = number of moles/total vol (L)
number of moles = 2.24 g/40.0 g mole^-1
volume = 0.5000 L
hence calculate molarity (take care with sig figs)