if you wish to warm 95 kg of water by 20.0c for your bath how much heat is required
A mother sheep and its lamb are both running at 3.0 m/s towards the carrol. The sheep has a mass of 60kg and the lamb has a mass of 20kg
What is the kinetic energy of the sheep
To calculate the amount of heat required to warm the water, you can use the specific heat capacity of water. The specific heat capacity of water is generally considered to be approximately 4.18 Joules per gram per degree Celsius (J/g°C) or 4.18 kJ/kg°C.
Given:
Mass of water (m): 95 kg
Temperature change (ΔT): 20.0 °C
The formula to calculate the amount of heat (Q) required is:
Q = m * c * ΔT
Substituting the given values:
Q = 95 kg * 4.18 kJ/kg°C * 20.0 °C
Calculating this expression:
Q = 7,930 kJ
Therefore, approximately 7,930 kilojoules of heat would be required to warm 95 kg of water by 20.0 °C for your bath.