.46 gm of magnesium produces .7667 gm of magnesium oxide,.3 gm of magnesium liberates 280 ml of hydrogen at NTP from an acid and 1.26 gm of water is produce by combination of 1.12 gm of oxygen with hydrogen which law of chemical combination can be illustrated with these data

To determine which law of chemical combination can be illustrated with the given data, let's analyze the information provided:

1. 0.46 gm of magnesium produces 0.7667 gm of magnesium oxide - This is an example of the Law of Definite Proportions, which states that a compound always contains the same elements in the same proportion by mass. In this case, the mass of magnesium oxide is a constant multiple of the mass of magnesium.

2. 0.3 gm of magnesium liberates 280 ml of hydrogen at NTP from an acid - This is an example of the Law of Multiple Proportions, which states that when two elements form multiple compounds, the ratio of the masses of one element that combines with a fixed mass of the other element can be expressed in small whole numbers. Here, the ratio of the masses of magnesium and hydrogen is 0.3 gm:280 ml.

3. 1.26 gm of water is produced by the combination of 1.12 gm of oxygen with hydrogen - This is an example of the Law of Conservation of Mass, which states that matter can neither be created nor destroyed in a chemical reaction. The total mass of the reactants (oxygen and hydrogen) equals the total mass of the product (water).

Therefore, the given data illustrates all three laws of chemical combination: the Law of Definite Proportions, the Law of Multiple Proportions, and the Law of Conservation of Mass.