If the pressure outside a window drops by 9.1%, while the pressure inside does not change, what is the force on the window? Assume that the area of the window is 2.3 m2.
The net force will be 9.1% of
Po*A
where Po is (normal) atmospheric pressure (10^5 N/m^2) and A = 2.3 m^2.
To determine the force on the window, we can use the formula:
Force = Pressure * Area
Given that the pressure outside the window drops by 9.1%, we can calculate the new pressure outside the window.
New Pressure = Original Pressure - (Original Pressure * 9.1%)
Since the pressure inside the window does not change, the pressure inside is equal to the original pressure outside.
Now, we substitute the values into the formula:
Force = (New Pressure) * Area
To get the answer, we need to know the original pressure outside the window. If you have that information, you can substitute it into the formula to calculate the force on the window.