The width of a rectangle is 4 meters more then 1/3 its lenght. the perimeter is 64. Find the lenght and width
L = Lenght
W = Width
P = Perimeter
P = 64 m
W = 4 + L / 3
P = 2 * ( W + L ) = 64 m
64 = 2 * ( 4 + L / 3 + L ) Divide both sides with 2
32 = 4 + L / 3 + L
32 - 4 = L / 3 + L
28 = 4 L / 3 Multiply both sides with 3
28 * 3 = 4 L
84 = 4 L Divide both sides with 4
84 / 4 = L
L = 21 m
W = 4 + L / 3
W = 4 + 21 / 3
W = 4 + 7 = 11 m
Lenght = 21 m
Width = 11 m
P = 2 * ( W + L ) = 2 * ( 11 + 21 ) = 2 32 = 64 m
what is the lenght of a ractangale is 1cm more then twice is width.the diagonal of this rectang is 3 more than twice its find the with of this rectangle ?? and you can put both x on each side the equation should be equal to zero .
To find the length and width of the rectangle, we can set up a system of equations based on the information given.
Let's let "l" represent the length of the rectangle, and "w" represent the width.
According to the problem, the width is 4 meters more than 1/3 of the length. So we can write an equation:
w = (1/3)l + 4
We also know that the perimeter of a rectangle is found by adding up all its sides, which in this case would be:
P = 2l + 2w
The perimeter is given as 64 meters, so we can set up another equation:
64 = 2l + 2w
Now that we have our system of equations, we can solve for the length and width.
First, substitute the expression for "w" from the first equation into the second equation:
64 = 2l + 2((1/3)l + 4)
Simplify the equation by distributing:
64 = 2l + (2/3)l + 8
Combine like terms:
64 = (8/3)l + 2l + 8
Simplify further by getting rid of fractions. We can do this by multiplying every term by 3 to eliminate the fraction:
192 = 8l + 6l + 24
Combine like terms again:
192 = 14l + 24
Subtract 24 from both sides:
168 = 14l
Divide both sides by 14:
l = 12
Now that we know the length is 12 meters, we can substitute this value back into the first equation to find the width:
w = (1/3)(12) + 4
w = 4 + 4
w = 8
Therefore, the length is 12 meters, and the width is 8 meters.