okay , so I had this questions on quiz today and I don't even remember the question properly but i wanted to know how you solve so I can see if I got it right
questions : Imagine a college student is looking her chances of getting interview calls from
A= calgary
B= california
P(A)=0.054
P(B)= 0.24
P(A/B)= 0.056
Imagine she get s call from calgary , whats the probability that she will get a call from California too ?
I used P(AandB)=P(A)P(B)
or should I have used
P(AorB)= P(A)+P(B)-P(AandB)
so you look like mixed toast ha ha
What the hell ?
To find the probability of getting a call from California given that she already received a call from Calgary (P(B/A)), you need to use the conditional probability formula.
The formula you used, P(A and B) = P(A) * P(B), gives you the probability of both events A and B happening simultaneously. However, this is not what you need to find in this case.
The correct formula to use is:
P(B/A) = P(A and B) / P(A)
In this case, P(A and B) represents the probability of getting a call from both Calgary and California, which is not given directly in the question. But there is another piece of information provided, P(A/B), which is the probability of getting a call from Calgary given that she already received a call from California.
To find P(A and B), you can use the formula:
P(A and B) = P(B) * P(A/B)
Now you have all the necessary values to calculate P(B/A) using the formula mentioned above:
P(B/A) = P(A and B) / P(A)
P(B/A) = (P(B) * P(A/B)) / P(A)
Substituting the given values:
P(B/A) = (0.24 * 0.056) / 0.054
Simplifying the expression:
P(B/A) ≈ 0.2496 / 0.054
P(B/A) ≈ 4.62
So, the approximate probability that she will get a call from California, given that she already received a call from Calgary, is 4.62%.