The length of a rectangle is 9 in. more than twice its width. If the perimeter of the rectangle is 48 in., find the width of the rectangle.

a) 4 in
b) 5 in
c) 6 in
d) 7 in

Call width = w

then the length is 2w+9
the perimeter is twice the length + twice the width
48 = 2 (2w+9) + 2 (w)

Let's start by representing the width of the rectangle as x inches.

According to the given information, the length of the rectangle is 9 inches more than twice its width.
So, the length can be represented as 2x + 9 inches.

The formula for the perimeter of a rectangle is:
Perimeter = 2 * (length + width)

Plugging in the values we have:
48 = 2 * (2x + 9 + x)

Simplifying the equation:
48 = 2 * (3x + 9)
48 = 6x + 18
48 - 18 = 6x
30 = 6x

To find the value of x, we divide both sides of the equation by 6:
30/6 = x
5 = x

Therefore, the width of the rectangle is 5 inches.

So, the answer is option b) 5 in.

To find the width of the rectangle, we can start by setting up equations using the given information.

Let's denote the width of the rectangle as "w" in inches.

According to the problem, the length of the rectangle is 9 inches more than twice its width. Therefore, the length is given by the expression "2w + 9".

The perimeter of a rectangle is given by the formula: 2(length + width).

So, the perimeter of this rectangle is: 2((2w + 9) + w) = 48 inches.

We can simplify this equation: 2(3w + 9) = 48.

Simplifying further, we get: 6w + 18 = 48.

Subtracting 18 from both sides: 6w = 30.

Dividing both sides by 6: w = 5.

Therefore, the width of the rectangle is 5 inches. So, the correct answer is option b) 5 in.