Suppose the mass of ball F is 0.5·kg. What is the impulse delivered to the ball by the floor?
Ball going south at velocity 4 m/s, hits floor and returns north velocity at 1 m/s
change in velocity = +1 - (-4) = 5
impulse = mass * change in velocity = change in momentum = .5*5 = 2.5
To find the impulse delivered to the ball by the floor, we need to calculate the change in momentum of the ball. The impulse is the product of the average force applied to an object and the time interval over which the force is applied.
The change in momentum of the ball can be calculated by subtracting its initial momentum from its final momentum. Momentum is given by the formula: momentum = mass × velocity.
Initial momentum of the ball (before collision):
Momentum = mass × velocity
= 0.5 kg × (-4 m/s)
= -2 kg⋅m/s
Final momentum of the ball (after collision):
Momentum = mass × velocity
= 0.5 kg × 1 m/s
= 0.5 kg⋅m/s
Change in momentum:
Delta momentum = Final momentum - Initial momentum
= 0.5 kg⋅m/s - (-2 kg⋅m/s)
= 0.5 kg⋅m/s + 2 kg⋅m/s
= 2.5 kg⋅m/s
Therefore, the impulse delivered to the ball by the floor is 2.5 kg⋅m/s.