physics

A rock falls from rest a vertical distance of 0.63 meters to the surface of a planet in 0.48 seconds. What is the magnitude of the acceleration due to gravity on that planet?

asked by Isaiah
  1. d = Vo*t + 0.5g*t^2 = 0.63m,
    0 + 0.5g*(0.48)^2 = 0.63,
    0.1152g = 0.63,
    g = 5.47m/s^2.

    posted by Henry

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