How do I calculate the concentration of KmNO4 when..

Initial Volume is 50mL
0.11g sodium oxalate
Volume of KMnO4 used to titrate oxalate and acid= 34.0 mL
Volume of KMnO4 used to titrate acid only= 0.10 mL

Please help me
Thank you!

Write the equation between C2O4^2 and MnO4^- and balance it.

Convert 0.11 g Na2C2O4 to moles. moles = grams/molar mass.
Use the coefficients in the balanced equation from above to convert moles oxalate to moles permanganate.
Then M MnO4^- = moles MnO4^-/L MnO4^-

To calculate the concentration of KMnO4, you need to use the concept of stoichiometry and the balanced chemical equation between KMnO4 and sodium oxalate.

First, let's find the number of moles of sodium oxalate (Na2C2O4) using its molar mass. The molar mass of sodium oxalate is 134 g/mol.

Number of moles of Na2C2O4 = Mass of Na2C2O4 / Molar mass of Na2C2O4
= 0.11 g / 134 g/mol

Next, since the balanced chemical equation between KMnO4 and Na2C2O4 is 5Na2C2O4 + 2KMnO4 + 8H2SO4 → 10CO2 + 2MnSO4 + 10Na2SO4 + 8H2O, we can calculate the number of moles of KMnO4 consumed using the stoichiometric ratio.

Number of moles of KMnO4 consumed = Number of moles of Na2C2O4 * (2 moles KMnO4 / 5 moles Na2C2O4)

Now, let's calculate the concentration of KMnO4.

Concentration of KMnO4 = Number of moles of KMnO4 consumed / Volume of KMnO4 used

Please plug in the values into the equation and calculate the concentration of KMnO4.

To calculate the concentration of KMnO4, we need to use the concept of stoichiometry. The balanced chemical equation for the reaction between KMnO4 and sodium oxalate is as follows:

5Na2C2O4 + 2KMnO4 + 8H2SO4 → 2MnSO4 + 10CO2 + 2K2SO4 + 8H2O + 5Na2SO4

From the equation, we can see that 2 moles of KMnO4 react with 5 moles of sodium oxalate.

1. First, calculate the number of moles of sodium oxalate used in the titration:
- Given mass of sodium oxalate = 0.11 g
- Molar mass of sodium oxalate (Na2C2O4) = 133.9992 g/mol
- Moles of sodium oxalate = (0.11 g) / (133.9992 g/mol)

2. Next, calculate the number of moles of KMnO4 used to titrate the sodium oxalate and acid:
- Given volume of KMnO4 used = 34.0 mL
- Molarity of KMnO4 = (number of moles of sodium oxalate) / (volume of KMnO4 used)

3. Now, determine the number of moles of KMnO4 used to titrate the acid only:
- Given volume of KMnO4 used = 0.10 mL
- Molarity of KMnO4 used in the acid titration = (number of moles of sodium oxalate) / (volume of KMnO4 used)

4. To find the concentration of KMnO4 in the solution, we need to compare the volume used to titrate the acid only to the volume used to titrate the sodium oxalate and acid:
- Given volume of KMnO4 used to titrate sodium oxalate and acid = 34.0 mL
- Given volume of KMnO4 used to titrate acid only = 0.10 mL
- Calculate the ratio: (volume of KMnO4 used to titrate acid only) / (volume of KMnO4 used to titrate sodium oxalate and acid)

5. Finally, calculate the concentration of KMnO4 using the ratio and molarity of KMnO4 used in the acid titration:
- Concentration of KMnO4 = (molarity of KMnO4 used in the acid titration) * (ratio calculated in step 4)

By following these steps, you can calculate the concentration of KMnO4 in the solution.