a force of 20n applied parallel to the surface of a horizontal table is just sufficient to make a block of mass 4.kg move on the table caculate thd coefficient of friction between the block and the table
I'm assuming you're referring to kinetic friction here, in either case (static or kinetic friction) however the following method is able to find the answer.
Friction=mass*g*friction constant
In this case the force of friction is equal and opposite to 20N, so Friction= -20.
-20=mgk
-20=4(-9.8)k
-20=-39.2k
k=.5102 N/m
To calculate the coefficient of friction between the block and the table, we need to use the equation that relates force of friction to the normal force and coefficient of friction. The normal force is the force exerted by a surface to support the weight of the object resting on it.
Here's the step-by-step process to solve the problem:
Step 1: Determine the normal force.
The normal force is equal to the weight of the block, which can be calculated by multiplying the mass (4 kg) by the acceleration due to gravity (9.8 m/s^2).
Weight (W) = mass (m) × acceleration due to gravity (g)
W = 4 kg × 9.8 m/s^2
W = 39.2 N
Step 2: Determine the force of friction.
The force of friction can be calculated using the equation:
Force of friction (Ff) = coefficient of friction (μ) × normal force (N)
We need to find the coefficient of friction, so rearrange the equation:
Coefficient of friction (μ) = Force of friction (Ff) / Normal force (N)
Given that the force applied (parallel to the surface) is 20 N, we can conclude that the force of friction is also 20 N.
Step 3: Calculate the coefficient of friction.
Coefficient of friction (μ) = Force of friction (Ff) / Normal force (N)
Coefficient of friction (μ) = 20 N / 39.2 N
Coefficient of friction (μ) ≈ 0.51
Therefore, the coefficient of friction between the block and the table is approximately 0.51.