Gasohol is a fuel containing ethanol (C2H5OH) that burns in oxygen (O2) to give CO2 and water. How many moles of O2 are needed to completely react with 2.50 moles of ethanol?
C2H5OH + 3O2 ==> 2CO2 + 3H2O
2.5 moles C2H5OH x (3 moles O2/1 mole C2H5OH) = 2.5 x (3/1) = ?
To calculate the number of moles of oxygen (O2) needed to completely react with 2.50 moles of ethanol (C2H5OH), we need to consider the balanced chemical equation for the combustion reaction:
C2H5OH + O2 → CO2 + H2O
From the balanced equation, we can see that the stoichiometric ratio between ethanol and oxygen is 1:1. This means that for every 1 mole of ethanol, 1 mole of oxygen is needed.
Therefore, the number of moles of oxygen needed to completely react with 2.50 moles of ethanol is also 2.50 moles.
To find the number of moles of oxygen (O2) needed to react with 2.50 moles of ethanol (C2H5OH), we need to use the balanced chemical equation for the combustion of ethanol.
The balanced equation for the reaction is:
C2H5OH + O2 → CO2 + H2O
From the balanced equation, we can see that 1 mole of ethanol reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide (CO2) and 1 mole of water (H2O).
Therefore, the number of moles of oxygen required is equal to the number of moles of ethanol.
So, in this case, the number of moles of O2 needed to react with 2.50 moles of ethanol is also 2.50 moles.