what is the coefficient on oxygen in the balanced equation for the following hydrocarbon combustion reacton

C7H14 + O2 + CO2 + H2o

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To determine the coefficient of oxygen in the balanced equation for the hydrocarbon combustion reaction, we need to balance the equation.

The given unbalanced equation is:
C7H14 + O2 → CO2 + H2O

First, let's count the number of carbon (C) atoms and hydrogen (H) atoms on both sides of the equation.

On the reactant side, we have 7 carbon atoms from C7H14 and none from O2. We also have 14 hydrogen atoms from C7H14 and none from O2.

On the product side, we have one carbon atom from CO2 and none from H2O. We also have two hydrogen atoms from H2O and none from CO2.

Since we have an equal number of carbon and hydrogen atoms on both sides, we can now focus on balancing the oxygen (O) atoms.

On the reactant side, we have no oxygen atoms from C7H14 and at least two oxygen atoms from O2.

On the product side, we have two oxygen atoms from CO2 and one oxygen atom from H2O.

To balance the oxygen atoms, we must have the same number on both sides. Since there are three oxygen atoms on the product side, we need three oxygen atoms on the reactant side.

Therefore, the balanced equation is:
C7H14 + 11O2 → 7CO2 + 7H2O

The coefficient on oxygen in the balanced equation is 11.