a.) Assume that you had 100 nuts (N) and 75 bolts (B). How many NB molecules could you make by screwing one nut onto each bolt?
b.) How many N2B molecules could you make by screwing two nuts onto each bolt?
for a) there is a 1:1 ratio. The bolts are the limiting reactant (which means you will run out of them before you use up all of the other) therefore you can only have 75 NB molecules.
b) for every N2B you have to have 2 nuts to every 1 bolt which is a 2:1 ratio so you divide the 100 nuts by 2. that will give you 50 nuts which will then become your limiting reactant. So you can make 50 N2B molecules.
To determine the number of molecules we can make by screwing nuts onto bolts, we need to consider the stoichiometry of the reaction.
a.) For each nut (N) and bolt (B) combination, we can produce one molecule of NB. Therefore, the number of NB molecules we can make is equal to the minimum of the number of nuts or bolts. In this case, we have 100 nuts and 75 bolts, so we can make a maximum of 75 NB molecules.
b.) To make N2B molecules, we need two nuts (N) for each bolt (B). So, we need to consider the total number of nuts and bolts we have and divide it by 2. Since we have 100 nuts and 75 bolts, we take the minimum between the number of nuts and bolts and divide it by 2. This gives us (minimum(100, 75))/2 = 50/2 = 25 N2B molecules.
In summary:
a.) The maximum number of NB molecules that can be made is 75.
b.) The number of N2B molecules that can be made is 25.