Using the data collected for part c on your data sheet and assuming the density of the vinegar is 1.00g/mL,

1) calculate the molar concentration of acetic acid (CH3COOH) in the vinegar sample using the average volume of NaOH.
2) calculate the mass percent of acetic acid in the vinegar sample.

Average volume NaOH: 28.94mL
Volume of vinegar: 5.00mL

See your post above.

To calculate the molar concentration of acetic acid (CH3COOH) in the vinegar sample, we need to use the following formula:

Molarity (M) = moles of solute / volume of solution (in L)

1) First, we need to convert the volume of NaOH from mL to L:

Volume of NaOH = 28.94 mL = 28.94 / 1000 L

2) Next, we need to determine the moles of NaOH. In the neutralization reaction between NaOH and acetic acid, the stoichiometric ratio is 1:1. This means that each mole of NaOH reacts with one mole of acetic acid.

moles of NaOH = Molarity of NaOH x Volume of NaOH (in L)

Since the Molarity of NaOH is not provided in the question, we need to check the data sheet for the concentration of NaOH used in the experiment.

3) Once we have determined the moles of NaOH, we can calculate the moles of acetic acid (CH3COOH) since the stoichiometric ratio is 1:1.

moles of acetic acid = moles of NaOH

4) Now we can calculate the molar concentration of acetic acid in the vinegar sample:

Molarity (CH3COOH) = moles of acetic acid / volume of vinegar (in L)

Given that the volume of vinegar is 5.00 mL, we need to convert it to liters:

Volume of vinegar = 5.00 mL = 5.00 / 1000 L

5) Calculate the molar concentration of acetic acid:

Molarity (CH3COOH) = moles of acetic acid / volume of vinegar (in L)

To calculate the mass percent of acetic acid in the vinegar sample, we need to use the following formula:

Mass percent = (mass of acetic acid / mass of vinegar) x 100%

1) Calculate the mass of acetic acid:

mass of acetic acid = moles of acetic acid x molar mass of acetic acid

The molar mass of acetic acid (CH3COOH) can be found on the periodic table. Add up the atomic masses of each element in the molecule:
CH3COOH: (12.01 g/mol x 2) + (1.01 g/mol x 3) + (16.00 g/mol) + (1.01 g/mol) = 60.05 g/mol

2) Calculate the mass of vinegar:

mass of vinegar = density of vinegar x volume of vinegar

Given that the density of vinegar is 1.00 g/mL and the volume of vinegar is 5.00 mL, we can calculate the mass of vinegar.

3) Calculate the mass percent of acetic acid:

Mass percent = (mass of acetic acid / mass of vinegar) x 100%