A pitcher throws a fast ball horizontally at 42.1 m/s How far does it drop before crossing the plate, 18.3 meters away?
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To find the distance the ball drops before crossing the plate, we can use the principles of projectile motion. In this case, we have a horizontal velocity of 42.1 m/s and the ball travels 18.3 meters horizontally.
First, we need to determine the time it takes for the ball to travel horizontally. We can use the formula:
time = distance / velocity
Plugging in the values, we have:
time = 18.3 m / 42.1 m/s
time = 0.435 seconds
Since the ball is thrown horizontally, there is no initial vertical velocity. However, the ball experiences a downward acceleration due to gravity of approximately 9.8 m/s².
To find the distance the ball drops vertically, we need to use the formula:
distance = 0.5 * acceleration * time²
Plugging in the values, we have:
distance = 0.5 * 9.8 m/s² * (0.435 s)²
distance ≈ 0.975 meters
Therefore, the ball drops approximately 0.975 meters vertically before crossing the plate.